關(guān)于冪運算經(jīng)典題,冪運算這個問題很多朋友還不知道,今天小六來為大家解答以上的問題,現(xiàn)在讓我們一起來看看吧!
1、1.(2/3)^1998*(1.5)^1997*(-1)^1999 =(2/3)^1998*(3/2)^1997*(-1)^1999 =(2/3)*(-1) =-2/3 2.(x^3)^2/[(x^4)^3/(x^3)^3]^3 =(x^3)^2/[(x^4/x^3)^3]^3 =(x^3)^2/[x^3]^3 =1/x^3 3.4-(-2)^-2-3^-2/(3.14-π)^0 =4-1/4-1/9 =131/36 4.[(-n)^2]^5/[(-n*n^3)^2*2n^2] =n^10/[n^8*2n^2] =n^10/2*n^10 =1/2 5.(-3*3^-2)^-3-(-3^2)^2 =(-1/3)^(-3)-3^4 =-3^3-3^4 =-27-81 =-108 6.x^m*x^m+x^(p+1)*x^(p-1)-x^m+1*x^m-1 =x^2m+x^2p-x^2m =x^2p 7.(a+b)(b+a)*(b+a)^2+(a+b)^2*(-a-b)^2 =(a+b)^4+(a+b)^4 =2(a+b)^4 8.2x*x^5+(-x)^2*x*(-x)^7 =2x^6-x^10 9.b^n+2*b*b^2-b^n*b^2*b^3 =b^n+2b^3-b^(n+5) 10.(x+y-z)^3n*(z-x-y)^2n*(x-z+y)^5n =(x+y-z)^3n*[-(x+y-z)]^2n*(x+y-z)^5n =(x+y-z)^10n。
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